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# Complete and Balance the Following Molecular Equation Answer

A molecular equation is an equation in which, on the left side, we write the substances entering the reaction and, on the right side, the formulas of the substances resulting from that reaction. For example, NaOH+HCl -> NaCl+H2O.

The following examples are the most common in homework assignments.

 Equation Answer HBRaq)+CA(OH)2(aq)→ 2HBr (aq) + Ca(OH)2 (aq) ==> CaBr2 (aq) + 2H2O (l) CU(OH)2(s)+HCLO4(aq)→ Cu(OH)2(s) + 2HClO4(aq) → Cu(ClO4)2 (aq) + 2H2O (l) write the ionic equation showing ions where possible Cu(OH)2(s) + 2H+(aq) + 2ClO4-(aq) → Cu2+(aq) + 2ClO4-(aq) + 2H2O(l) Write the net ionic equation by deleting anything that is common to both sides of → Cu(OH)2(s) + 2H+(aq) → Cu2+(aq) + 2H2O(l) Al(OH)3 (s) + 3HNO3 (s) 3 HNO3 (aq) + Al(OH)3 (s) → Al(NO3)3 (aq) + 3 H2O (l) cadmium chloride + sodium sulfide molecular equation Na2S (aq) + CdCl2 (aq) → 2 NaCl (aq) + CdS (s) This is a precipitation reaction: CdS is the formed precipitate. K2SO4(aq)+CaI2(aq)→CaSO4(s)+KI(aq) K2SO4(aq) + CaI2(aq) → CaSO4(s) + KI(aq) Balance K – K2SO4(aq) + CaI2(aq) → CaSO4(s) + 2 KI(aq) Balanced reaction – K2SO4(aq) + CaI2(aq) → CaSO4(s) + 2 KI(aq) ▪ K2SO4(aq) → 2 K+(aq) + SO42-(aq) ▪ CaI2(aq) → Ca2+(aq) + 2 I-(aq) ▪ 2 KI(aq) → 2 K+(aq) + 2 I-(aq) sodium carbonate + sulfuric acid molecular equation H2SO4 (aq) + Na2CO3 (aq) → Na2SO4 (aq) + H2O (l) + CO2 (g) This is an acid-base reaction (neutralization): H2SO4 is an acid, Na2CO3 is a base. Write the balanced molecular equation for the neutralization reaction between HCL and BA(OH)2 2 HCl (aq) + Ba(OH)2 (aq) → BaCl2 (aq) + 2 H2O (l) This is an acid-base reaction (neutralization): HCl is an acid, Ba(OH)2 is a base. Write the balanced molecular equation for the neutralization reaction between HI and BA(OH)2 2 HI(aq) + Ba²⁺(aq) + 2 OH⁻(aq) → 2 H₂O(l) + Ba²⁺(aq) + 2I⁻(aq) Explanation: Let’s consider the following balanced molecular equation. 2 HI(aq) + Ba(OH)₂(aq) → 2 H₂O(l) + BaI₂(aq) In the complete ionic equation, we include all the ions and the species that do not dissociate in water. HI is a weak electrolyte so it exists mostly in the molecular form. H₂O has a very low equilibrium constant (Kw = 10⁻¹⁴) si it exists mainly in the molecular form. 2 HI(aq) + Ba²⁺(aq) + 2 OH⁻(aq) → 2 H₂O(l) + Ba²⁺(aq) + 2I⁻(aq) Write the balanced molecular equation for the neutralization reaction between h2so4 and koh 2 KOH (aq) + H2SO4 (aq) → K2SO4 (aq) + 2 H2O (l) This is an acid-base reaction (neutralization): KOH is a base, H2SO4 is an acid. Complete sodium acetate + hydrochloric acid molecular equation Balanced – NaCH3COO(aq) + HCl(aq) –> NaCl(aq) + CH3COOH(aq)   Complete Ionic – Na+ +CH3COO- + H+ + Cl- –> Na+ + Cl- + CH3COO- + H+ There is no net ionic equation because all of the ions cancel out–there is no reaction because all of the products are soluble in water. Complete molecular equation for copper II sulfate and sodium phosphate 3 CuSO4 + 2 Na3PO4 → 3 Na2SO4 + Cu3(PO4)2

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